[clue] Unzipping zip archives with duplicates?

[Sean LeBlanc]

In case anyone was interested, I used Ruby to do this. The script looks 
like this. It could probably be tightened up, and probably has some edge 
cases it won't handle, but for now, it will do.

Dirty details: I needed this to be cross-platform - it will run in a CI 
server that is Linux, but developers may use it on their clients, which 
might be Windows, OS X, or Linux.

Ultimately, it will most likely be launched by Ant - modern versions now 
support a "script" task that utilizes Apache's BSF which implements 
JSR-223 - which means that with the JRuby jar, I can run Ruby within Ant 
without shelling out. This is so I don't have to write all the crufty 
Ant stuff to detect OS version, and then try to either guess where the 
ruby binary might be installed or what shell to launch....bash or 
cmd...which is a long way of saying "this is why there isn't a shebang 
at the top of the script".

A sample call might look like:

$ ruby unzip.rb file_with_dupes.zip directoryToUnzipIn


unzip.rb contents:


require 'rubygems'
require 'zip/zip'

def unzip_file (file, destination)
   Zip::ZipFile.open(file) { |zip_file|
    zip_file.each { |f|
      f_path=File.join(destination, f.name)
      f_path_try = f_path
      versionNumber = 1
      while File.file?(File.dirname(f_path_try))
        f_path_try = File.join(File.dirname(f_path) + "." + 
versionNumber.to_s , f.name)
        versionNumber = versionNumber + 1
      end

      versionNumber = 1
      f_path_final = f_path_try
      while File.exist?(f_path_final)
        f_path_final = f_path_try + "." + versionNumber.to_s
        versionNumber = versionNumber + 1
      end
      puts f_path_final
      FileUtils.mkdir_p(File.dirname(f_path_final))
      zip_file.extract(f, f_path_final) unless File.exist?(f_path_final)
    }
   }
end

if (ARGV.size == 2) then
  unzip_file(ARGV[0], ARGV[1])
end