[clue] Dumb disk question
foo7775
foo7775 at comcast.net
Fri Oct 23 16:46:13 MDT 2015
Crap, I saw that earlier this week... <facepalms>
Thanks Dan, I appreciate it.
T.
On 10/23/2015 4:39 PM, Dan Kulinski wrote:
> If you do want to see if there is a file system directly on the block
> device, try file -s /dev/sdb. This will look for the magic number in
> common locations. I just learned this because I knew how the file
> command worked on files and wondered if it knew about file systems.
> Sure enough, it does!
>
> On Fri, Oct 23, 2015 at 4:35 PM, Dan Kulinski <daniel at kulinski.net
> <mailto:daniel at kulinski.net>> wrote:
>
> Do you know what type of file system it is supposed to be? If
> there is no partition table then the file system should be taking
> up the whole device. The way you limit the size of a file system,
> generally, is to create a partition.
>
> On Fri, Oct 23, 2015 at 4:30 PM, foo7775 <foo7775 at comcast.net
> <mailto:foo7775 at comcast.net>> wrote:
>
> Hey all, first off, I am _very_ aware that this is a
> painfully-basic question, but this has been a rough week, so
> please bear with me...
>
> I've been searching for this info for a while now, but my
> very-tired brain doesn't appear to be able to format the
> search terms appropriately. What I'm wanting to do is to
> confirm that a defined disk (/dev/sdb in this case) is
> essentially "a raw partition" & doesn't have any data on it.
> If I can confirm that, then I can create the needed
> partitions/filesystems & turn it over to the customer. The
> 'fdisk' utility shows me this:
>
> Disk /dev/sdb: 214.7 GB, 214748364800 bytes
> 255 heads, 63 sectors/track, 26108 cylinders
> Units = cylinders of 16065 * 512 = 8225280 bytes
> Sector size (logical/physical): 512 bytes / 512 bytes
> I/O size (minimum/optimal): 512 bytes / 512 bytes
> Disk identifier: 0x00000000
>
> Now I can tell that it doesn't contain any partitions on it
> (i.e. sdb1, sdb2, etc.), but I just can't seem to remember how
> to confirm that it isn't formatted as a single big partition.
> I'd be grateful if someone could refresh my memory on this...
>
> Thanks,
>
> T.
>
>
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