[clue] Dumb disk question
David L. Willson
DLWillson at TheGeek.NU
Fri Oct 23 18:05:28 MDT 2015
Cool! Trying that later.
Sent from my Verizon Wireless 4G LTE smartphone
-------- Original message --------
From: Dan Kulinski <daniel at kulinski.net>
Date: 10/23/2015 4:39 PM (GMT-07:00)
To: CLUE's mailing list <clue at cluedenver.org>
Subject: Re: [clue] Dumb disk question
If you do want to see if there is a file system directly on the block device, try file -s /dev/sdb. This will look for the magic number in common locations. I just learned this because I knew how the file command worked on files and wondered if it knew about file systems. Sure enough, it does!
On Fri, Oct 23, 2015 at 4:35 PM, Dan Kulinski <daniel at kulinski.net> wrote:
Do you know what type of file system it is supposed to be? If there is no partition table then the file system should be taking up the whole device. The way you limit the size of a file system, generally, is to create a partition.
On Fri, Oct 23, 2015 at 4:30 PM, foo7775 <foo7775 at comcast.net> wrote:
Hey all, first off, I am _very_ aware that this is a painfully-basic
question, but this has been a rough week, so please bear with me...
I've been searching for this info for a while now, but my
very-tired brain doesn't appear to be able to format the search
terms appropriately. What I'm wanting to do is to confirm that a
defined disk (/dev/sdb in this case) is essentially "a raw
partition" & doesn't have any data on it. If I can confirm
that, then I can create the needed partitions/filesystems & turn
it over to the customer. The 'fdisk' utility shows me this:
Disk /dev/sdb: 214.7 GB, 214748364800
bytes
255 heads, 63 sectors/track, 26108
cylinders
Units = cylinders of 16065 * 512 =
8225280 bytes
Sector size (logical/physical): 512
bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes
/ 512 bytes
Disk identifier: 0x00000000
Now I can tell that it doesn't contain any partitions on it (i.e.
sdb1, sdb2, etc.), but I just can't seem to remember how to confirm
that it isn't formatted as a single big partition. I'd be grateful
if someone could refresh my memory on this...
Thanks,
T.
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