[clue] python (function return array) [programming]

[Mike Bean]

would

def foo():
      return [my_list(0), my_list(1), my_list(2)]

work?

The immediate problem I can think of is that the lists aren't always going
to be same length.

Bean

On Tue, Dec 27, 2011 at 6:38 PM, Nick Pascucci <npascut1 at gmail.com> wrote:

> Hi Mike,
>
> You can return lists just like any other variable in Python. When you
> iterate over it, just remember that the returned value was a list, and not
> a single value. You don't need to make it into a tuple or wrap it in
> another list like in your example. Here's a demo for you:
>
> def foo():
>     return ["baz", "bar", "quux"]
>
> my_list = foo()
> for x in my_list:
>     print x  # Prints "baz\nbar\nquuz"
>
> If you do like in your example, and put my_list = [foo()] you'll have a
> list of lists containing your desired list. Probably not what you're
> looking for.
>
> Hope that helps,
> Nick
>
>
>
> On Tue, Dec 27, 2011 at 7:18 PM, Mike Bean <beandaemon at gmail.com> wrote:
>
>> OK, I'm pretty sure this is a fairly novice question, but I'm working a
>> project on my own and my attempts to suss the solution have met with
>> limited success.
>> I'm writing mostly similar code over and over again, bad me.  But I have
>> to be able to return a list/array, and I don't know if return statement can
>> handle more then just a single variable.  So for example, I realize your
>> generic scenario is
>>
>> def function()
>>      variable="whatever"
>>      return(variable)
>>
>> newvar=function()
>> print("newvar")
>>
>> but I want to know is what's wrong with my logic in this sense:
>>
>> def function()
>>      my_array=[1,2,3]
>>      return(my_array)
>>
>> new_array=[(my_array)]
>> for x in new_array:
>>      print(x)
>>
>> testing has met with no success obviously.  I'm assuming it's because an
>> array is not the same thing as a generic variable.  In any case, any
>> suggestions/guidance from folks with experience in programming/python is
>> appreciated.
>>
>> Bean
>>
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>
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